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Question
How will you convert ethanoic acid into propanoic acid?
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Solution
\[\ce{\underset{Ethanoic acid}{CH3COOH} ->[LiAlH4][Reduction] \underset{Ethanol}{CH3CH2OH} ->[P/I2] \underset{Ethyl iodide}{CH3CH2I} ->[KCN][-KI] \underset{Ethyl cyanide}{CH3CH2CN} ->[H2O/H+] \underset{Propanoic acid}{CH3CH2COOH}}\]
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