Advertisements
Advertisements
Question
How much is the angular distance between the Tropic of Cancer and Tropic of Capricorn?
Short Answer
Advertisements
Solution
- The angular distance between Tropic of Cancer and the equator is 23°30' and that between Tropic of Capricorn and the equator is 23°30'.
- Since both of these parallels lie on either side of the equator, the total angular distance between both of them is 23°30' + 23°30' = 46°60' = 47°.
shaalaa.com
Concept of Latitudes
Is there an error in this question or solution?
RELATED QUESTIONS
What is the latitude of the equator?
What is the latitude of Arctic Circle? Also, give its characteristics.
Fill in the blanks.
The Arctic Circle is located in the ____________ hemisphere.
All parallels of latitude converge at the equator.
Using a globe, write down the names of the countries through which the equator passes.
The line of latitude which is known as the Great Circle is ______________.
Choose the odd one.
The region from the Equator towards the Tropic of Cancer is known as ______.
Name the following:
23½°S
Name the following:
66½°N
