Advertisements
Advertisements
Question
How much is the angular distance between the Tropic of Cancer and Tropic of Capricorn?
Short Answer
Advertisements
Solution
- The angular distance between Tropic of Cancer and the equator is 23°30' and that between Tropic of Capricorn and the equator is 23°30'.
- Since both of these parallels lie on either side of the equator, the total angular distance between both of them is 23°30' + 23°30' = 46°60' = 47°.
shaalaa.com
Concept of Latitudes
Is there an error in this question or solution?
RELATED QUESTIONS
Give a geographical reason for lines of latitude carve out the heat zones of the earth.
What is meant by “the Parallels of Latitude?
What is the latitude of Equator? Also give its characteristics.
Mid-days Sun can be seen overhead in Chennai twice a year, but not even once in Delhi. Why?
Complete the following table.
| Characteristics | Parallels of latitude | Meridians of longitude |
| Shape | ||
| Size | Size of each parallel is different. | |
| Distance | Distance between two meridians is larger on the equator and the same decreases towards the Poles. |
The North Pole is ______.
The imaginary lines drawn horizontally on Earth.
The region from the Equator towards the Tropic of Cancer is known as ______.
How many parallels are found on the Earth?
Latitudes are also known as ______.
