How much is the angular distance between the Tropic of Cancer and Tropic of Capricorn?

Short Answer

The angular distance between Tropic of Cancer and the equator is 23°30' and that between Tropic of Capricorn and the equator is 23°30'.
Since both of these parallels lie on either side of the equator, the total angular distance between both of them is 23°30' + 23°30' = 46°60' = 47°.

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Concept of Latitudes

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Chapter 1: The Earth and the Graticule - Exercises [Page 9]

Chapter 1 The Earth and the Graticule
Exercises | Q (D) (2) | Page 9

Chapter 1 The Earth and the Graticule
Exercises | Q (D) (2) | Page 127

What is latitude of North pole and South pole?

How are Latitudes measured?

What is the latitude of North Pole? Also, give its characteristics.

Explain why there is no higher latitude other than 90° N and 90° S.

All parallels of latitude converge at the equator.

Complete the following table.

Characteristics	Parallels of latitude	Meridians of longitude
Shape
Size	Size of each parallel is different.
Distance		Distance between two meridians is larger on the equator and the same decreases towards the Poles.

choose the odd one.

The region from the Equator towards the Tropic of Cancer is known as ______.

How many parallels are found on the Earth?

The Sun’s rays fall vertically in this region ______.