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प्रश्न
How much is the angular distance between the Tropic of Cancer and Tropic of Capricorn?
लघु उत्तर
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उत्तर
- The angular distance between Tropic of Cancer and the equator is 23°30' and that between Tropic of Capricorn and the equator is 23°30'.
- Since both of these parallels lie on either side of the equator, the total angular distance between both of them is 23°30' + 23°30' = 46°60' = 47°.
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Concept of Latitudes
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
संबंधित प्रश्न
What is the latitude of Tropic of Cancer?
How are Latitudes measured?
Explain why there is no higher latitude other than 90° N and 90° S.
Name the five important parallels of latitude.
Complete the following table.
| Characteristics | Parallels of latitude | Meridians of longitude |
| Shape | ||
| Size | Size of each parallel is different. | |
| Distance | Distance between two meridians is larger on the equator and the same decreases towards the Poles. |
Choose the odd one.
The latitude which divides the Earth into two halves ______.
How many parallels are found on the Earth?
Give Reasons:
The length of the lines of latitude decreases from the equator.
The Sun’s rays fall vertically in this region ______.
