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प्रश्न
How much is the angular distance between the Tropic of Cancer and Tropic of Capricorn?
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उत्तर
- The angular distance between Tropic of Cancer and the equator is 23°30' and that between Tropic of Capricorn and the equator is 23°30'.
- Since both of these parallels lie on either side of the equator, the total angular distance between both of them is 23°30' + 23°30' = 46°60' = 47°.
संबंधित प्रश्न
Mention two characteristics of lines of latitude.
What is the latitude of Equator? Also give its characteristics.
Fill in the blanks.
The Arctic Circle is located in the ____________ hemisphere.
Using a globe, write down the names of the countries through which the equator passes.
Complete the following table.
| Characteristics | Parallels of latitude | Meridians of longitude |
| Shape | ||
| Size | Size of each parallel is different. | |
| Distance | Distance between two meridians is larger on the equator and the same decreases towards the Poles. |
The imaginary lines drawn horizontally on Earth.
The regions on Earth between North & South lines of latitude (66 ½°) and poles (90°) is called Frigid Zone.
Tropic of Cancer is Otherwise called as ______.
The region from the Equator towards the Tropic of Cancer is known as ______.
Give Reasons:
The region from the Equator towards the Tropic of Cancer (23‘/2°N) and the Tropic of Capricorn (23!4°S) is called Torrid Zone.
