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प्रश्न
How much is the angular distance between the Tropic of Cancer and Tropic of Capricorn?
लघु उत्तर
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उत्तर
- The angular distance between Tropic of Cancer and the equator is 23°30' and that between Tropic of Capricorn and the equator is 23°30'.
- Since both of these parallels lie on either side of the equator, the total angular distance between both of them is 23°30' + 23°30' = 46°60' = 47°.
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Concept of Latitudes
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
संबंधित प्रश्न
What is the latitude of the equator?
What is the latitude of Tropic of Capricorn?
What is the relation between Temperature and Latitude of a place?
State two properties of lines of latitude.
What is the latitude of North Pole? Also, give its characteristics.
What is the latitude of Arctic Circle? Also, give its characteristics.
Name the five important parallels of latitude.
Parallels and meridians are imaginary lines.
Tropic of Cancer is Otherwise called as ______.
Name the following:
23½°N
