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How much is the angular distance between the Tropic of Cancer and Tropic of Capricorn? - Geography

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प्रश्न

How much is the angular distance between the Tropic of Cancer and Tropic of Capricorn? 

लघु उत्तरीय
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उत्तर

  1. The angular distance between Tropic of Cancer and the equator is 23°30' and that between Tropic of Capricorn and the equator is 23°30'.
  2. Since both of these parallels lie on either side of the equator, the total angular distance between both of them is 23°30' + 23°30' = 46°60' = 47°.
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Concept of Latitudes
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अध्याय 1: The Earth and the Graticule - Exercises [पृष्ठ ९]

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बालभारती Geography [English] Standard 6 Maharashtra State Board
अध्याय 1 The Earth and the Graticule
Exercises | Q (D) (2) | पृष्ठ ९
बालभारती Geography Integrated [English] Standard 6 Maharashtra State Board
अध्याय 1 The Earth and the Graticule
Exercises | Q (D) (2) | पृष्ठ १२७
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