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प्रश्न
How much is the angular distance between the Tropic of Cancer and Tropic of Capricorn?
लघु उत्तरीय
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उत्तर
- The angular distance between Tropic of Cancer and the equator is 23°30' and that between Tropic of Capricorn and the equator is 23°30'.
- Since both of these parallels lie on either side of the equator, the total angular distance between both of them is 23°30' + 23°30' = 46°60' = 47°.
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Concept of Latitudes
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
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