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प्रश्न
How much is the angular distance between the Tropic of Cancer and Tropic of Capricorn?
लघु उत्तरीय
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उत्तर
- The angular distance between Tropic of Cancer and the equator is 23°30' and that between Tropic of Capricorn and the equator is 23°30'.
- Since both of these parallels lie on either side of the equator, the total angular distance between both of them is 23°30' + 23°30' = 46°60' = 47°.
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Concept of Latitudes
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
संबंधित प्रश्न
Give a geographical reason for lines of latitude carve out the heat zones of the earth.
Which is the longest line of latitude?
State two properties of lines of latitude.
What is the latitude of the Tropic of Capricorn? Also, give its characteristics.
Mid-days Sun can be seen overhead in Chennai twice a year, but not even once in Delhi. Why?
Name the five important parallels of latitude.
Which circle forms the eastern and western hemispheres?
Complete the following table.
| Characteristics | Parallels of latitude | Meridians of longitude |
| Shape | ||
| Size | Size of each parallel is different. | |
| Distance | Distance between two meridians is larger on the equator and the same decreases towards the Poles. |
The region from the Equator towards the Tropic of Cancer is known as ______.
Give Reasons:
The length of the lines of latitude decreases from the equator.
