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Question
How much electricity is required in coulomb for the oxidation of 1 mol of H2O to O2?
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Solution
The electrode reaction for 1 mol of H2O is given as:
\[\ce{H2O -> H2 + 1/2 O2}\]
i.e., \[\ce{O^{2-} -> 1/2O2 + 2e^-}\]
∴ Amount of electricity required = 2 F
= 2 × 96500 C
= 193000 C
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