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Question
Write the reaction occurring at anode and cathode and the products of electrolysis of aq KCl.
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Solution
\[\ce{KCl (aq) -> K+(aq) + Cl-(aq)}\]
Cathode: \[\ce{H2O(l) + e- -> 1/2 H2(g) + OH-(aq)}\]
Anode: \[\ce{Cl-(aq) -> 1/2Cl2(aq) + e-}\]
Net reaction: \[\ce{KCl(aq) + H2O(l) -> K+(aq) + OH-(aq) + 1/2H2(g) + 1/2Cl2(g)}\]
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