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Question
How is methoxy benzene prepared from carbolic acid?
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Solution
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\[\begin{array}{cc}
\phantom{....................}\ce{O}\phantom{.....................................}\ce{O}\phantom{.}\\
\phantom{....................}||\phantom{......................................}||\phantom{.}\\
\phantom{}\ce{CH3 - CH = CH - CH2 - C - CH3 -> CH3 - CH = CH - CH2 - C - OH}\phantom{.}
\end{array}\]
Match the reactions given in Column I with the suitable reagents given in Column II.
| Column I (Reactions) |
Column II (Reagents) |
| (i) Benzophenone Diphenylmethane | (a) \[\ce{LiAlH4}\] |
| (ii) Benzaldehyde 1-Phenylethanol | (b) \[\ce{DIBAL-H}\] |
| (iii) Cyclohexanone Cyclohexanol | (c) \[\ce{Zn(Hg)/Conc. HCl}\] |
| (iv) Phenyl benzoate Benzaldehyde | (d) \[\ce{CH3MgBr}\] |
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| List - I | List - II | ||
| (a) |  \[\ce{->[CO,HCl][Anhyd. AlCl3/CuCl]}\] |
(i) | Hell-Volhard-Zelinsky reaction |
| (b) |
\[\begin{array}{cc}
\ce{O}\phantom{.................}\\ ||\phantom{.................}\\ \ce{R - C - CH3 + NaOX ->} \end{array}\] |
(ii) | Gattermann-Koch reaction |
| (c) | \[\ce{R - CH2 - OH + R'COOH ->[Conc. H2SO4]}\] | (iii) | Haloform reaction |
| (d) | \[\ce{R - CH2COOH ->[(i) X2/Red P][(ii) H2O]}\] | (iv) | Esterification |
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