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Question
How many electrons are flowing per second past a point in a circuit in which there is a current of 5 amp?
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Solution
Current, I = 5 A
Time, t = 1 s
Using the relation, I = Q / t:
Q = I x t
= 5 x 1 = 5 C
Now, if the charge is `1.6xx10^-19C` the number of electrons is one.
So, if the charge is 5C, the number of electrons is given by:
`1/(1.6xx10^-19)xx5=31.25xx10^18`
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