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Karnataka Board PUCPUC Science 2nd PUC Class 12

Given the standard electrode potentials, K+/K = −2.93 V, Ag+/Ag = 0.80 V, Hg2+/Hg = 0.79 V Mg2+/Mg = −2.37 V, Cr3+/Cr = −0.74 V Arrange these metals in their increasing order of reducing power. - Chemistry

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Question

Given the standard electrode potentials,

K+/K = −2.93 V, Ag+/Ag = 0.80 V,

Hg2+/Hg = 0.79 V

Mg2+/Mg = −2.37 V, Cr3+/Cr = −0.74 V

Arrange these metals in their increasing order of reducing power.

Short Answer
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Solution

A metal’s oxidation potential determines its reducing power. Its tendency to be oxidised and, thus, its reducing power increase with its oxidation potential. Therefore, the following will be the order in which the power of the specified metals increases or decreases:

Ag < Hg < Cr < Mg < K

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Chapter 2: Electrochemistry - Exercises [Page 59]

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NCERT Chemistry Part 1 and 2 [English] Class 12
Chapter 2 Electrochemistry
Exercises | Q 2.2 | Page 59
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