English
Karnataka Board PUCPUC Science 2nd PUC Class 12

Arrange the following metals in the order in which they displace each other from the solution of their salts. Al, Cu, Fe, Mg and Zn - Chemistry

Advertisements
Advertisements

Question

Arrange the following metals in the order in which they displace each other from the solution of their salts.

\[\ce{Al, Cu, Fe, Mg}\] and \[\ce{Zn}\]

One Line Answer
Advertisements

Solution

\[\ce{Mg, Al, Zn, Fe}\] and \[\ce{Cu}\]

shaalaa.com
  Is there an error in this question or solution?
Chapter 2: Electrochemistry - Exercises [Page 59]

APPEARS IN

NCERT Chemistry Part 1 and 2 [English] Class 12
Chapter 2 Electrochemistry
Exercises | Q 2.1 | Page 59

RELATED QUESTIONS

Derive a relation between ΔH and ΔU for a chemical reaction. Draw neat labelled diagram of calomel electrode. Resistance and conductivity of a cell containing 0.001 M KCI solution at 298K are 1500Ω and 1.46x10-4 S.cm-1 respectively.


Can you store copper sulphate solutions in a zinc pot?


Why cannot we store AgNO3 solution in copper vessel?


A solution of CuSO4 is electrolysed using a current of 1.5 amperes for 10 minutes. What mass of Cu is deposited at cathode? [Atomic mass of Cu = 63.7]


How many faradays of electricity are required for the following reaction to occur

\[\ce{MnO^-_4 -> Mn^2+}\]


Zinc can be coated on iron to produce galvanized iron but the reverse is not possible. It is because ____________.


Assertion: pure iron when heated in dry air is converted with a layer of rust.

Reason: Rust has the compositionFe3O4.


In the electrochemical cell: Zn|ZnSO4 (0.01 M)||CuSO4 (1.0 M)|Cu, the emf of this Daniel cell is E1. When the concentration of ZnSO4 is changed to 1.0 M and that CuSO4 changed to 0.01 M, the emf changes to E2. From the above, which one is the relationship between E1 and E2?


A gas X at 1 atm is bubbled through a solution containing a mixture of 1 MY and 1 MZ at 25°C. If the reduction potential of Z > Y > X, then ______.


`E_(cell)^Θ` = 1.1V for Daniel cell. Which of the following expressions are correct description of state of equilibrium in this cell?

(i) 1.1 = `K_c`

(ii) `(2.303RT)/(2F) logK_c` = 1.1

(iii) `log K_c = 2.2/0.059`

(iv) `log K_c` = 1.1


A galvanic cell has electrical potential of 1.1V. If an opposing potential of 1.1V is applied to this cell, what will happen to the cell reaction and current flowing through the cell?


Match the terms given in Column I with the items given in Column II.

Column I Column II
(i) Λm (a) intensive property
(ii) ECell (b) depends on number of ions/volume
(iii) K (c) extensive property
(iv) ∆rGCell (d) increases with dilution

Assertion: Mercury cell does not give steady potential.

Reason: In the cell reaction, ions are not involved in solution.


The correct order of the mobility of the alkali metal ions. In aqueous solultion is


On which electrode the oxidation reaction takes place?


If the value of Ksp for Hg2Cl2 (s) is X then the value of X will be ____ where pX = - log X.
Given:

\[\ce{Hg2Cl2 + 2e- -> 2Hg(l) + 2Cl-}\],  E° = 0.27 V

\[\ce{Hg+2 + 2e- -> 2Hg(l)}\]   E° = 0.81 V


The number of moles of electrons passed when the current of 2 A is passed through a solution of electrolyte for 20 minutes is ______.


The two half cell reaction of an electrochemical cell is given as 

\[\ce{Ag+ + e- -> Ag}\], `"E"_("Ag"^+//"Ag")^circ` = - 0.3995 V

\[\ce{Fe^{2+} -> Fe^{3+} + e-}\], `"E"_("Fe"^{3+}//"Fe")^{2+}` = - 0.7120 V

The value of EMF will be ______.


Can we construct an electrochemical cell with two half-cells composed of ZnSO4 solution and zinc electrodes? Explain your answer.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×