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Question
`E_(cell)^Θ` = 1.1V for Daniel cell. Which of the following expressions are correct description of state of equilibrium in this cell?
(i) 1.1 = `K_c`
(ii) `(2.303RT)/(2F) logK_c` = 1.1
(iii) `log K_c = 2.2/0.059`
(iv) `log K_c` = 1.1
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Solution
(ii) `(2.303RT)/(2F) logK_c` = 1.1
(iii) `log K_c = 2.2/0.059`
Explanation:
`E_(cell)^Θ = (2.303RT)/(2F) logK_c`
or `E_(cell)^Θ = 0.059/2 log K_c` or 1.1 = `0.059/2 loc K_c`
or `log K_C = 2.2/0.059`
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