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EcellΘ = 1.1V for Daniel cell. Which of the following expressions are correct description of state of equilibrium in this cell? - Chemistry

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प्रश्न

`E_(cell)^Θ` = 1.1V for Daniel cell. Which of the following expressions are correct description of state of equilibrium in this cell?

(i) 1.1 = `K_c`

(ii) `(2.303RT)/(2F) logK_c` = 1.1

(iii) `log K_c = 2.2/0.059`

(iv) `log K_c` = 1.1

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उत्तर

(ii) `(2.303RT)/(2F) logK_c` = 1.1

(iii) `log K_c = 2.2/0.059`

Explanation:

`E_(cell)^Θ = (2.303RT)/(2F) logK_c`

or `E_(cell)^Θ = 0.059/2 log K_c` or 1.1 = `0.059/2 loc K_c`

or `log K_C = 2.2/0.059`

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अध्याय 3: Electrochemistry - Exercises [पृष्ठ ३७]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 12
अध्याय 3 Electrochemistry
Exercises | Q II. 20. | पृष्ठ ३७

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