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How Many Electrons Flow Through a Metllic Wire If a Current of 0·5 a is Passed for 2 Hours? (Given : 1 F = 96,500 C Mol−1)

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प्रश्न

How many electrons flow through a metllic wire if a current of 0·5 A is passed for 2 hours? (Given : 1 F = 96,500 C mol−1)

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उत्तर

I = 0.5 A

t = 2 hours = 2 × 60 × 60 s = 7200 s

Thus, Q = It

= 0.5 A × 7200 s

= 3600 C

We know that 96500 C = 6.023 × 1023 number of electrons.

Then,

3600 C = `(6.023 xx 10^23 xx 3600)/96500` number of electrons

= 2.25 x 1022 number of electrons

Hence 2.25 x 1022 number of electrons will flow through the wire

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2016-2017 (March) All India Set 3

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