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Question
Depict the galvanic cell in which the reaction \[\ce{Zn_{(s)} + 2Ag+_{( aq)} -> Zn^{2+}_{( aq)} + 2Ag_{(s)}}\] takes place. Further show:
- Which of the electrode is negatively charged?
- The carriers of the current in the cell.
- Individual reaction at each electrode.
Short Answer
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Solution
The set-up will be similar to that shown below:

The cell will be represented as:
\[\ce{Zn_{(s)} | Zn^{2+}_{( aq)} || Ag^+_{( aq)} | Ag_{(s)}}\]
- The zinc electrode (anode) is negatively charged because oxidation occurs at the anode.
-
- External circuit: Electrons flow from Zn to Ag, so the conventional current flows from Ag to Zn.
- Salt bridge: Ions carry the current.
- At anode: \[\ce{Zn_{(s)} -> Zn^{2+}_{( aq)} + 2e–}\]
At cathode: \[\ce{Ag+_{( aq)} + e- -> Ag_{(s)}}\]
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