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Question
What is the formula of a compound in which the element Y forms hcp lattice and atoms of X occupy 2/3rd of tetrahedral voids?
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Solution
Suppose the number of atoms Y in hcp lattice = n
As the number of tetrahedral voids is double the number of atoms in close packing, the number of tetrahedral voids = 2n
As atoms X occupy 2/3rd of the tetrahedral voids, the number of atoms X in the lattice
`2/3xx2n=(4n)/3`
`:. "Ratio of X:Y"=(4n)/3:n=4/3:1=4:3`
Hence, the formula of the compound is X4Y3.
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