Advertisements
Advertisements
प्रश्न
What is the formula of a compound in which the element Y forms hcp lattice and atoms of X occupy 2/3rd of tetrahedral voids?
Advertisements
उत्तर
Suppose the number of atoms Y in hcp lattice = n
As the number of tetrahedral voids is double the number of atoms in close packing, the number of tetrahedral voids = 2n
As atoms X occupy 2/3rd of the tetrahedral voids, the number of atoms X in the lattice
`2/3xx2n=(4n)/3`
`:. "Ratio of X:Y"=(4n)/3:n=4/3:1=4:3`
Hence, the formula of the compound is X4Y3.
संबंधित प्रश्न
How will you distinguish between the following pair of terms?
Tetrahedral and octahedral voids
A compound is formed by two elements A and B. The element B forms cubic close packing and atoms of A occupy `1/3"rd"` of tetrahedral voids. The formula of this compound is ____________.
What is the coordination number of sodium in Na2O?
Percentages of free space in cubic close packed structure and in the body-centered packed structure are respectively:
In the hexagonal close-packed structure of a metallic lattice, the number of nearest neighbours of a metallic atom is ____________.
In the cubic close packing, the unit cell has ______.
In which of the following arrangements octahedral voids are formed?
(i) hcp
(ii) bcc
(iii) simple cubic
(iv) fcc
The number of tetrahedral voids per unit cell in NaCl crystal is:
(i) 4
(ii) 8
(iii) twice the number of octahedral voids.
(iv) four times the number of octahedral voids.
Show that in a cubic close packed structure, eight tetrahedral voids are present per unit cell.
In which of the following structures coordination number for cations and anions in the packed structure will be same?
