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Question
For a given ideal gas 6 × 105 J heat energy is supplied and the volume of gas is increased from 4 m3 to 6 m3 at atmospheric pressure. Calculate
- the work done by the gas
- change in internal energy of the gas
- graph this process in PV and TV diagram
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Solution
Heat energy supplied to gas Q = 6 × 105 J
Change in volume ∆V = (6 – 4) = 2 m3
1 atm = 1.013 × 105 Nm−2
a. Work done by the gas W = P × ∆V
= 1.013 × 105 × 2
= 2.026 × 105
W = 202.6 kJ
b. Change in internal energy of the gas
∆U = Q − P. ∆V
= 6 × 105 − (202.6 × 103)
= 6 × 105 − 2.026 × 105
= 3.974 × 105
∆U = 397.4 kJ
c.
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