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Question
Find the weight of solid rectangular iron piece of size 50 cm × 40 cm × 10cm, if 1 cm3 of iron weighs 8 gm.
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Solution
\[\text { The dimension of the rectangular piece of iron is 50 cm }\times 40 cm \times 10 cm . \]
\[\text { i . e . , volume } = 50 cm \times 40 cm \times 10 cm = 20000 {cm}^3 \]
\[\text { It is given that the weight of 1 }{cm}^3 \text { of iron is 8 gm } . \]
\[ \therefore \text { The weight of the given piece of iron = 20000 } \times 8 gm\]
\[ = 160000 gm\]
\[ = 160 \times 1000 gm\]
\[ = 160 kg ( \because 1 kg = 1000 gm)\]
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