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Find the Weight of Solid Rectangular Iron Piece of Size 50 Cm × 40 Cm × 10cm, If 1 Cm3 Of Iron Weighs 8 Gm. - Mathematics

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प्रश्न

Find the weight of solid rectangular iron piece of size 50 cm × 40 cm × 10cm, if 1 cm3 of iron weighs 8 gm.

थोडक्यात उत्तर
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उत्तर

\[\text { The dimension of the rectangular piece of iron is 50 cm }\times 40 cm \times 10 cm . \]

\[\text { i . e . , volume } = 50 cm \times 40 cm \times 10 cm = 20000 {cm}^3 \]

\[\text { It is given that the weight of 1 }{cm}^3 \text { of iron is 8 gm } . \]

\[ \therefore \text { The weight of the given piece of iron = 20000 } \times 8 gm\]

\[ = 160000 gm\]

\[ = 160 \times 1000 gm\]

\[ = 160 kg ( \because 1 kg = 1000 gm)\]

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पाठ 21: Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - Exercise 21.1 [पृष्ठ ८]

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आरडी शर्मा Mathematics [English] Class 8
पाठ 21 Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube)
Exercise 21.1 | Q 10 | पृष्ठ ८

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