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Question
Find the values of p and q so that x4 + px3 + 2x3 − 3x + q is divisible by (x2 − 1).
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Solution
Let f(x) = x4 + px3 + 2x3 − 3x + q and `g(x) = x^2 - 1`be the given polynomials.
We have,
`g(x)= x^2 - 1`
` = (x-1)(x+ 1)`
Here, (x-1),(x+1)are the factor of g(x).
If f(x) is divisible by (x-1)and (x+1), then (x-1)and (x+1) are factor of f(x).
Therefore, f(1) and f(−1) both must be equal to zero.
Therefore,
`f(1) = (1)^4 + p(a)^3 + 2(1)^2 - 3(1)+q` ......... (1)
`⇒ 1+ p + 2 - 3 + q = 0`
`p+q = 0`
and
`f(-1) = (-1)^4 + p(-1)^3 + 2(- 1)^2 - 3(-1) + q = 0`
` 1-p+2 + 3 +q = 0`
`-p + q = -6 ......(2)`
Adding both the equations, we get,
`(p+q) + (-p + q) = -6`
`2q = -6`
`q = -3`
Putting this value in (i)
`p+(-3) = 0`
`p = 3`
Hence, the value of p and q are 3, −3 respectively.
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