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Find the Two Consecutive Natural Numbers Whose Product is 20.

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Question

Find the two consecutive natural numbers whose product is 20.

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Solution

Let the two consecutive natural numbers be ‘x’ and ‘x + 2’

⇒ Given that the product of the natural numbers is 20

Hence ⇒ x(x + 1) = 20

⇒ ๐‘ฅ2 + ๐‘ฅ = 20

⇒ ๐‘ฅ2 + ๐‘ฅ - 20 = 0

⇒ ๐‘ฅ2 + 5๐‘ฅ - 4๐‘ฅ - 20 = 0

⇒ ๐‘ฅ(๐‘ฅ + 5) - 4(๐‘ฅ + 5) = 0

⇒ ๐‘ฅ = -5 ๐‘œ๐‘Ÿ ๐‘ฅ = 4

Considering positive value of x as x ∈ N

For r = 4, x + 1 = 4 + 1 = 5

∴ The two consecutive natural numbers are 4 as 5.

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Chapter 4: Quadratic Equations - Exercise 4.7 [Page 51]

APPEARS IN

R.D. Sharma Mathematics [English] Class 10
Chapter 4 Quadratic Equations
Exercise 4.7 | Q 7 | Page 51

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