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The Product of Shikha'S Age Five Years Ago and Her Age 8 Years Later is 30, Her Age at Both Times Being Given in Years. Find Her Present Age. - Mathematics

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Question

The product of Shikha's age five years ago and her age 8 years later is 30, her age at both times being given in years. Find her present age.

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Solution

Let the present age of Shikha be x years

Then, 8 years later, age of her = (x + 8) years

Five years ago, her age = (x - 5) years

Then according to question,

(x - 5)(x + 8) = 30

x2 + 8x - 5x - 40 = 30

x2 + 3x - 40 - 30 = 0

x2 + 3x - 70 = 0

x2 - 7x + 10x - 70 = 0

x(x - 7) + 10(x - 7) = 0

(x - 7)(x + 10) = 0

So, either 

x- 7 = 0

x = 7

Or

x + 10 = 0

x = -10

But the age never be negative

Hence, the present age of Shikha be 7 years.

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Chapter 4: Quadratic Equations - Exercise 4.9 [Page 61]

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RD Sharma Mathematics [English] Class 10
Chapter 4 Quadratic Equations
Exercise 4.9 | Q 3 | Page 61

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