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Find the two consecutive natural numbers whose product is 20.
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Let the two consecutive natural numbers be ‘x’ and ‘x + 2’
⇒ Given that the product of the natural numbers is 20
Hence ⇒ x(x + 1) = 20
⇒ ЁЭСе2 + ЁЭСе = 20
⇒ ЁЭСе2 + ЁЭСе - 20 = 0
⇒ ЁЭСе2 + 5ЁЭСе - 4ЁЭСе - 20 = 0
⇒ ЁЭСе(ЁЭСе + 5) - 4(ЁЭСе + 5) = 0
⇒ ЁЭСе = -5 ЁЭСЬЁЭСЯ ЁЭСе = 4
Considering positive value of x as x ∈ N
For r = 4, x + 1 = 4 + 1 = 5
∴ The two consecutive natural numbers are 4 as 5.
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