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Solve the Following Quadratic Equations by Factorization: `3x^2-2sqrt6x+2=0`

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प्रश्न

Solve the following quadratic equations by factorization:

`3x^2-2sqrt6x+2=0`

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उत्तर

We have been given

`3x^2-2sqrt6x+2=0`

`3x^2-sqrt6x-sqrt6x+2=0`

`sqrt3x(sqrt3x-sqrt2)-sqrt2(sqrt3x-sqrt2)=0`

`(sqrt3x-sqrt2)(sqrt3x-sqrt2)=0`

Therefore,

`sqrt3x-sqrt2 = 0`

`sqrt3x=sqrt2`

`x=sqrt(2/3)`

or,

`sqrt3x-sqrt2 = 0`

`sqrt3x=sqrt2`

`x=sqrt(2/3)`

Hence, `x=sqrt(2/3)` or `x=sqrt(2/3)`

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अध्याय 4: Quadratic Equations - Exercise 4.3 [पृष्ठ २०]

APPEARS IN

आर.डी. शर्मा Mathematics [English] Class 10
अध्याय 4 Quadratic Equations
Exercise 4.3 | Q 42 | पृष्ठ २०

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