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Solve the Following Quadratic Equations by Factorization: `3x^2-2sqrt6x+2=0` - Mathematics

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Question

Solve the following quadratic equations by factorization:

`3x^2-2sqrt6x+2=0`

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Solution

We have been given

`3x^2-2sqrt6x+2=0`

`3x^2-sqrt6x-sqrt6x+2=0`

`sqrt3x(sqrt3x-sqrt2)-sqrt2(sqrt3x-sqrt2)=0`

`(sqrt3x-sqrt2)(sqrt3x-sqrt2)=0`

Therefore,

`sqrt3x-sqrt2 = 0`

`sqrt3x=sqrt2`

`x=sqrt(2/3)`

or,

`sqrt3x-sqrt2 = 0`

`sqrt3x=sqrt2`

`x=sqrt(2/3)`

Hence, `x=sqrt(2/3)` or `x=sqrt(2/3)`

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Chapter 4: Quadratic Equations - Exercise 4.3 [Page 20]

APPEARS IN

RD Sharma Mathematics [English] Class 10
Chapter 4 Quadratic Equations
Exercise 4.3 | Q 42 | Page 20

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