Advertisements
Advertisements
प्रश्न
In each of the following, determine whether the given values are solution of the given equation or not:
x2 - 3x + 2 = 0; x = 2, x = -1
Advertisements
उत्तर
Substitute x = 2 in L.H.S. of given equation
L.H.S. = (2)2 - 3x 2 x2
= 6 - 6
= 0
⇒ L.H.S. = 0
= R.H.S.
Substitute x = -1 in L.H.S. of given equation.
L.H.S. = (-1)2 - 3 x -1 + 2 = 0
= 1 + 3 + 2 ≠ 0 ≠ R.H.S.
x = 2 is a solution and x = -1 is not solution of the given equation.
संबंधित प्रश्न
Solve the following quadratic equation by factorization method: 9x2-25 = 0
Solve for x
`(2x)/(x-3)+1/(2x+3)+(3x+9)/((x-3)(2x+3)) = 0, x!=3,`
Solve the following quadratic equations by factorization:
(x − 4) (x + 2) = 0
Some students planned a picnic. The budget for food was Rs. 500. But, 5 of them failed to go and thus the cost of food for each member increased by Rs. 5. How many students attended the picnic?
For the equation given below, find the value of ‘m’ so that the equation has equal roots. Also, find the solution of the equation:
x2 – (m + 2)x + (m + 5) = 0
Solve the following quadratic equations by factorization:
(x + 1) (2x + 8) = (x+7) (x+3)
The values of k for which the quadratic equation \[16 x^2 + 4kx + 9 = 0\] has real and equal roots are
Solve equation using factorisation method:
x2 – 10x – 24 = 0
In a two digit number, the unit’s digit is twice the ten’s digit. If 27 is added to the number, the digit interchange their places. Find the number.
Solve the following equation by factorization
(x – 4)2 + 52 = 132
