Advertisements
Advertisements
प्रश्न
In each of the following, determine whether the given values are solution of the given equation or not:
x2 - 3x + 2 = 0; x = 2, x = -1
Advertisements
उत्तर
Substitute x = 2 in L.H.S. of given equation
L.H.S. = (2)2 - 3x 2 x2
= 6 - 6
= 0
⇒ L.H.S. = 0
= R.H.S.
Substitute x = -1 in L.H.S. of given equation.
L.H.S. = (-1)2 - 3 x -1 + 2 = 0
= 1 + 3 + 2 ≠ 0 ≠ R.H.S.
x = 2 is a solution and x = -1 is not solution of the given equation.
संबंधित प्रश्न
Find two numbers whose sum is 27 and product is 182.
Solve the following quadratic equations by factorization:
5x2 - 3x - 2 = 0
Solve the following quadratic equations by factorization:
a2x2 - 3abx + 2b2 = 0
Solve : x2 – 11x – 12 =0; when x ∈ N
Solve each of the following equations by factorization:
`2x^2-1/2x=0`
`4x^2+4sqrt3x+3=0`
Solve the following equation :
`("x" - 1)/("x" - 2) + ("x" - 3)/("x" - 4) = 3 1/3`
Two natural numbers differ by 4. If the sum of their square is 656, find the numbers.
Solve the following equation by factorization
3x2 – 5x – 12 = 0
A rectangle of area 105 cm² has its length equal to x cm. Write down its breadth in terms of x. Given that the perimeter is 44 cm, write down an equation in x and solve it to determine the dimensions of the rectangle.
