Advertisements
Advertisements
प्रश्न
In each of the following, determine whether the given values are solution of the given equation or not:
x2 - 3x + 2 = 0; x = 2, x = -1
Advertisements
उत्तर
Substitute x = 2 in L.H.S. of given equation
L.H.S. = (2)2 - 3x 2 x2
= 6 - 6
= 0
⇒ L.H.S. = 0
= R.H.S.
Substitute x = -1 in L.H.S. of given equation.
L.H.S. = (-1)2 - 3 x -1 + 2 = 0
= 1 + 3 + 2 ≠ 0 ≠ R.H.S.
x = 2 is a solution and x = -1 is not solution of the given equation.
संबंधित प्रश्न
Solve the following quadratic equations by factorization:
`a/(x - a) + b/(x - b) = (2c)/(x - c)`
Solve 2x2 – 9x + 10 =0; when x ∈ Q
`x^2-4x+1=0`
Solve the following quadratic equation by factorisation.
\[6x - \frac{2}{x} = 1\]
If the equation x2 − ax + 1 = 0 has two distinct roots, then
Solve the following equation: 3x2 + 25 x + 42 = 0
Solve the following equation: 25x (x + 1) = -4
Solve the following equation:
`(x - 1)/(2x + 1) + (2x + 1)/(x - 1) = 5/2 , x ≠-1/2`
Solve the following equation: `7"x" + 3/"x" = 35 3/5`
A farmer wishes to grow a 100m2 rectangular vegetable garden. Since he was with him only 30m barbed wire, he fences 3 sides of the rectangular garden letting the compound of his house to act as the 4th side. Find the dimensions of his garden .
