Advertisements
Advertisements
प्रश्न
The length of verandah is 3m more than its breadth. The numerical value of its area is equal to the numerical value of its perimeter.
(i) Taking x, breadth of the verandah write an equation in ‘x’ that represents the above statement.
(ii) Solve the equation obtained in above and hence find the dimension of verandah.
Advertisements
उत्तर
Let breadth = xm, length = (x + 3)m.
Area = x (x + 3) sq.m.
Perimeter = 2(x + x + 3) = (4x + 6)m.
According to the question, x(x + 3) = 4x + 6
⇒ x2 - x - 6 = 0
⇒ (x + 2) (x ++ 3) = 0
∴ x = 3 and x = -2 (inadmissiable).
Hence breadth = 3m, length = 6m.
संबंधित प्रश्न
Solve for x :
`3/(x+1)+4/(x-1)=29/(4x-1);x!=1,-1,1/4`
Solve the following quadratic equations by factorization:
`(2x)/(x-4)+(2x-5)/(x-3)=25/3`
The product of Ramu's age (in years) five years ago and his age (in years) nice years later is 15. Determine Ramu's present age.
Solve the following quadratic equations by factorization:
`(x-3)/(x+3 )+(x+3)/(x-3)=2 1/2`
The sum of a natural number and its square is 156. Find the number.
Find the values of k for which the roots are real and equal in each of the following equation:
\[4 x^2 - 2\left( k + 1 \right)x + \left( k + 1 \right) = 0\]
The area of the isosceles triangle is 60 cm2, and the length of each one of its equal side is 13cm. Find its base.
Solve the following equation by factorisation :
x2 + 6x – 16 = 0
Solve the following quadratic equation by factorization method.
3p2 + 8p + 5 = 0
Find the roots of the following quadratic equation by the factorisation method:
`3sqrt(2)x^2 - 5x - sqrt(2) = 0`
