Advertisements
Advertisements
प्रश्न
Solve the following equation: `("a+b")^2 "x"^2 - 4 "abx" - ("a - b")^2 = 0`
Advertisements
उत्तर
`("a+b")^2 "x"^2 - 4 "abx" - ("a - b")^2 = 0`
As, - (a + b)2 + (a - b)2 = - a2 - b2 - 2ab + a2 + b2 - 2ab = - 4ab
(a+b)2x2 -[(a+ b)2-(a-b)2] x - (a - b)2 = 0
(a+ b)2x2 - (a+ b)2x + (a - b)2x - (a - b)2 = 0
{(a+ b)2x} (x - 1) + {(a - b)2} (x - 1) = 0
(x - 1) [(a + b)2x + (a - b)2] = 0
x - 1 = 0 and (a + b)2x + (a - b)2 = 0
x = 1 and x = `-("a" - "b")^2/("a" + "b")^2`
x = 1 and x = `-(("a" - "b")/("a" + "b"))^2`
APPEARS IN
संबंधित प्रश्न
Solve the following quadratic equations by factorization:
(x − 4) (x + 2) = 0
Solve the following quadratic equations by factorization:
(2x + 3)(3x − 7) = 0
A girls is twice as old as her sister. Four years hence, the product of their ages (in years) will be 160. Find their present ages.
The perimeter of a rectangular field is 82 m and its area is 400 m2. Find the breadth of the rectangle.
Solve the following quadratic equations by factorization: \[2 x^2 + ax - a^2 = 0\]
Solve the following quadratic equations by factorization:
\[\frac{x - 2}{x - 3} + \frac{x - 4}{x - 5} = \frac{10}{3}; x \neq 3, 5\]
The sum of a number and its reciprocal is `2 9/40`. Find the number.
Solve equation using factorisation method:
(2x – 3)2 = 49
Rs. 7500 is divided equally among a certain number of children. Had there been 20 less children, each would have receive Rs 100 more. Find the original number of children.
Divide 16 into two parts such that the twice the square of the larger part exceeds the square of the smaller part by 164.
