Advertisements
Advertisements
प्रश्न
Solve the following equation : x2 + 2ab = (2a + b)x
Advertisements
उत्तर
x2 + 2ab = (2a + b )x
x2 + 2ab = 2ax +bx
x2 - 2ax - bx+ 2ab = 0
x (x - 2a) - b(x - 2a)= 0
(x - 2a)(x - b)= 0
x = 2a, x = b
APPEARS IN
संबंधित प्रश्न
Solve the following quadratic equations by factorization:
abx2 + (b2 – ac)x – bc = 0
The sum of the squares of the two consecutive odd positive integers as 394. Find them.
The sum of the squares of two consecutive positive even numbers is 452. Find the numbers.
The sum of two natural numbers is 9 and the sum of their reciprocals is `1/2`. Find the numbers .
Find the value of k for which the following equations have real and equal roots:
\[x^2 - 2\left( k + 1 \right)x + k^2 = 0\]
A two digit number is 4 times the sum of its digit and twice the product of its digit. Find the number.
Solve the following quadratic equation by factorisation:
9x2 - 3x - 2 = 0
Solve the following equation by factorization
`(1)/(x + 6) + (1)/(x - 10) = (3)/(x - 4)`
The sum of two numbers is 9 and the sum of their squares is 41. Taking one number as x, form ail equation in x and solve it to find the numbers.
Find three successive even natural numbers, the sum of whose squares is 308.
