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प्रश्न
Solve the following equation: `"a"("x"^2 + 1) - x("a"^2 + 1) = 0`
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उत्तर
`"a"("x"^2 + 1) - x("a"^2 + 1) = 0`
ax2 + a - a2x - x = 0
x2 + 1 - ax - `1/"a" "x" = 0`
x2 + 1 - ax - `1/"a" "x" + 1 = 0`
`"x"("x" - "a") - 1/"a" ("x" - "a") = 0`
`("x" - "a") ("x" - 1/"a") = 0`
x = a ; x = `1/ "a"`
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