Advertisements
Advertisements
प्रश्न
Solve the following equation: `"a"("x"^2 + 1) - x("a"^2 + 1) = 0`
Advertisements
उत्तर
`"a"("x"^2 + 1) - x("a"^2 + 1) = 0`
ax2 + a - a2x - x = 0
x2 + 1 - ax - `1/"a" "x" = 0`
x2 + 1 - ax - `1/"a" "x" + 1 = 0`
`"x"("x" - "a") - 1/"a" ("x" - "a") = 0`
`("x" - "a") ("x" - 1/"a") = 0`
x = a ; x = `1/ "a"`
APPEARS IN
संबंधित प्रश्न
The sum of two number a and b is 15, and the sum of their reciprocals `1/a` and `1/b` is 3/10. Find the numbers a and b.
A passenger train takes one hour less for a journey of 150 km if its speed is increased by 5 km/hr from its usual speed. Find the usual speed of the train.
A plane left 40 minutes late due to bad weather and in order to reach its destination, 1600 km away in time, it had to increase its speed by 400 km/hr from its usual speed. Find the usual speed of the plane.
The sum of a natural number and its square is 156. Find the number.
If −5 is a root of the quadratic equation\[2 x^2 + px - 15 = 0\] and the quadratic equation \[p( x^2 + x) + k = 0\] has equal roots, find the value of k.
A quadratic equation whose one root is 2 and the sum of whose roots is zero, is ______.
Solve the following quadratic equation:
4x2 - 4ax + (a2 - b2) = 0 where a , b ∈ R.
Solve the following equation by factorization
`(x^2 - 5x)/(2)` = 0
Find the values of x if p + 1 =0 and x2 + px – 6 = 0
A school bus transported an excursion party to a picnic spot 150 km away. While returning, it was raining and the bus had to reduce its speed by 5 km/hr, and it took one hour longer to make the return trip. Find the time taken to return.
