Advertisements
Advertisements
Question
Find the values of x if p + 7 = 0, q – 12 = 0 and x2 + px + q = 0,
Advertisements
Solution
p + 7 = 0, then p = – 7
and q – 12 = 0, then q = 12
Substituting the values of p and q in the given quadratic equation,
x2 – 7x + 12 = 0
⇒ x2 – 3x – 4x + 12 = 0
⇒ x(x – 3) – 4(x – 3) = 0
⇒ (x – 3) (x – 4) = 0
Either x – 3 = 0,
then x = 3
or
x – 4 = 0,
then x = 4
Hence x = 3, 4.
APPEARS IN
RELATED QUESTIONS
Solve the following quadratic equations by factorization:
`sqrt2x^2-3x-2sqrt2=0`
Determine two consecutive multiples of 3, whose product is 270.
Solve x2 – 4x – 12 =0; when x ∈ I
Solve 2x2 – 9x + 10 =0; when x ∈ Q
The sum of the squares of two consecutive positive integers is 365. Find the integers.
If \[1 + \sqrt{2}\] is a root of a quadratic equation will rational coefficients, write its other root.
Solve the following equation: 4x2 + 16x = 0
The hypotenuse of a right-angled triangle is 17cm. If the smaller side is multiplied by 5 and the larger side is doubled, the new hypotenuse will be 50 cm. Find the length of each side of the triangle.
Solve the following equation by factorization
(x – 4)2 + 52 = 132
Solve the following equation by factorization
`(8)/(x + 3) - (3)/(2 - x)` = 2
