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At t minutes past 2 pm, the time needed by the minutes hand of a clock to show 3 pm was found to be 3 minutes less than t24 minutes. Find t.

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Question

At t minutes past 2 pm, the time needed by the minutes hand of a clock to show 3 pm was found to be 3 minutes less than `t^2/4` minutes. Find t.

Sum
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Solution

We know that, the time between 2 pm to 3 pm = 1 h = 60 min

Given that, at f min past 2 pm, the time needed by the minute hand of a clock to show 3 pm was found to be 3 min less than `t^2/4` min

i.e., `t + (t^2/4 - 3)` = 60

⇒ 4t + t2 – 12 = 240

⇒ t2 + 4t – 252 = 0   

⇒ t2 + 18t – 14t – 252 = 0   .....[By splitting the middle term]

⇒ t(t + 18) – 14(t + 18) = 0   ....[Since, time cannot be negative, so t ≠ – 18]

⇒ (t + 18)(t – 14) = 0

∴ t = 14 min

Hence, the required value of t is 14 min.

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Chapter 4: Quadatric Euation - Exercise 4.4 [Page 43]

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NCERT Exemplar Mathematics Exemplar [English] Class 10
Chapter 4 Quadatric Euation
Exercise 4.4 | Q 8 | Page 43

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