Advertisements
Advertisements
प्रश्न
Find the values of x if p + 7 = 0, q – 12 = 0 and x2 + px + q = 0,
Advertisements
उत्तर
p + 7 = 0, then p = – 7
and q – 12 = 0, then q = 12
Substituting the values of p and q in the given quadratic equation,
x2 – 7x + 12 = 0
⇒ x2 – 3x – 4x + 12 = 0
⇒ x(x – 3) – 4(x – 3) = 0
⇒ (x – 3) (x – 4) = 0
Either x – 3 = 0,
then x = 3
or
x – 4 = 0,
then x = 4
Hence x = 3, 4.
APPEARS IN
संबंधित प्रश्न
Solve the equation `4/x-3=5/(2x+3); xne0,-3/2` for x .
Solve the following quadratic equations by factorization:
(x − 4) (x + 2) = 0
Solve the following quadratic equations by factorization:
4x2 + 5x = 0
Solve:
`1/p + 1/q + 1/x = 1/(x + p + q)`
For the equation given below, find the value of ‘m’ so that the equation has equal roots. Also find the solution of the equation:
3x2 + 12x + (m + 7) = 0
Find the values of k for which the quadratic equation \[\left( 3k + 1 \right) x^2 + 2\left( k + 1 \right)x + 1 = 0\] has equal roots. Also, find the roots.
Write the condition to be satisfied for which equations ax2 + 2bx + c = 0 and \[bx^2 - 2\sqrt{ac}x + b = 0\] have equal roots.
A two digit number is such that the product of the digit is 12. When 36 is added to the number, the digits interchange their places. Find the numbers.
Solve the following quadratic equation by factorisation method:
`x/(x + 1) + (x + 1)/x = (34)/(15') x ≠ 0, x ≠ -1`
Solve the following by reducing them to quadratic form:
`sqrt(x^2 - 16) - (x - 4) = sqrt(x^2 - 5x + 4)`.
