Advertisements
Advertisements
प्रश्न
Find the values of x if p + 7 = 0, q – 12 = 0 and x2 + px + q = 0,
Advertisements
उत्तर
p + 7 = 0, then p = – 7
and q – 12 = 0, then q = 12
Substituting the values of p and q in the given quadratic equation,
x2 – 7x + 12 = 0
⇒ x2 – 3x – 4x + 12 = 0
⇒ x(x – 3) – 4(x – 3) = 0
⇒ (x – 3) (x – 4) = 0
Either x – 3 = 0,
then x = 3
or
x – 4 = 0,
then x = 4
Hence x = 3, 4.
APPEARS IN
संबंधित प्रश्न
Find two numbers whose sum is 27 and product is 182.
Solve the following quadratic equations by factorization:
x2 + 2ab = (2a + b)x
Solve the following quadratic equations by factorization:
\[\frac{4}{x} - 3 = \frac{5}{2x + 3}, x \neq 0, - \frac{3}{2}\]
Write the set of value of k for which the quadratic equations has 2x2 + kx − 8 = 0 has real roots.
If one root of the equation 4x2 − 2x + (λ − 4) = 0 be the reciprocal of the other, then λ =
Solve the following by reducing them to quadratic form:
`sqrt(y + 1) + sqrt(2y - 5) = 3, y ∈ "R".`
In each of the following determine whether the given values are solutions of the equation or not.
x2 + 6x + 5 = 0; x = -1, x = -5
Solve the following equation by factorization
`(8)/(x + 3) - (3)/(2 - x)` = 2
Solve the following equation by factorization
`(x + 1)/(x - 1) + (x - 2)/(x + 2)` = 3
(x – 3) (x + 5) = 0 gives x equal to ______.
