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प्रश्न
Find the values of x if p + 7 = 0, q – 12 = 0 and x2 + px + q = 0,
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उत्तर
p + 7 = 0, then p = – 7
and q – 12 = 0, then q = 12
Substituting the values of p and q in the given quadratic equation,
x2 – 7x + 12 = 0
⇒ x2 – 3x – 4x + 12 = 0
⇒ x(x – 3) – 4(x – 3) = 0
⇒ (x – 3) (x – 4) = 0
Either x – 3 = 0,
then x = 3
or
x – 4 = 0,
then x = 4
Hence x = 3, 4.
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