Advertisements
Advertisements
प्रश्न
Find the values of x if p + 1 =0 and x2 + px – 6 = 0
Advertisements
उत्तर
p + 1 = 0, then p = – 1
Substituting the value of p in the given quadratic equation
x2 + ( – 1)x – 6 = 0
⇒ x2 – x – 6 = 0
⇒ x2 – 3x + 2x – 6 = 0
⇒ x(x – 3) + 2(x – 3) = 0
⇒ (x – 3) (x + 2) = 0
Either x – 3 = 0,
then x = 3
or
x + 2 = 0,
then x = – 2
Hence x = 3, -2.
APPEARS IN
संबंधित प्रश्न
Solve the following quadratic equations by factorization:
5x2 - 3x - 2 = 0
The time taken by a person to cover 150 km was 2.5 hrs more than the time taken in the return journey. If he returned at a speed of 10 km/hr more than the speed of going, what was the speed per hour in each direction?
Solve x2 – 4x – 12 =0; when x ∈ I
For the equation given below, find the value of ‘m’ so that the equation has equal roots. Also, find the solution of the equation:
x2 – (m + 2)x + (m + 5) = 0
Without solving the following quadratic equation Find the value of p for which the roots are equal
`px^2 - 4x + 3 = 0`
The sum of natural number and its positive square root is 132. Find the number.
Determine whether the values given against the quadratic equation are the roots of the equation.
x2 + 4x – 5 = 0 , x = 1, –1
Solve equation using factorisation method:
(x + 3)2 – 4(x + 3) – 5 = 0
If the product of two positive consecutive even integers is 288, find the integers.
The difference between the squares of two numbers is 45. The square of the smaller number is 4 times the larger number. Determine the numbers.
