Advertisements
Advertisements
प्रश्न
Solve equation using factorisation method:
`(x - 3)/(x + 3) + (x + 3)/(x - 3) = 2 1/2`
Advertisements
उत्तर
`(x - 3)/(x + 3) + (x + 3)/(x - 3) = 2 1/2`
⇒ `((x - 3)^2 + (x + 3)^2)/((x + 3) (x - 3)) = 5/2`
⇒ `(x^2 - 6x + 9 + x^2 + 6x + 9)/(x^2 - 9) = 5/2`
⇒ 2(2x2 + 18) = 5(x2 – 9)
⇒ 4x2 + 36 = 5x2 – 45
⇒ x2 – 81 = 0
⇒ x2 – 92 = 0
⇒ (x + 9)(x – 9) = 0
If x + 9 = 0 or x – 9 = 0
Then x = – 9 or x = 9
APPEARS IN
संबंधित प्रश्न
Solve for x :
`3/(x+1)+4/(x-1)=29/(4x-1);x!=1,-1,1/4`
Solve the following quadratic equations
(i) x2 + 5x = 0 (ii) x2 = 3x (iii) x2 = 4
Solve the following quadratic equations
(i) 7x2 = 8 – 10x
(ii) 3(x2 – 4) = 5x
(iii) x(x + 1) + (x + 2) (x + 3) = 42
Solve the following quadratic equations by factorization:
`x^2-(sqrt3+1)x+sqrt3=0`
The difference of two numbers is 4. If the difference of their reciprocals is 4/21. Find the numbers.
The hypotenuse of a right triangle is `3sqrt10`. If the smaller leg is tripled and the longer leg doubled, new hypotenuse wll be `9sqrt5`. How long are the legs of the triangle?
Solve the following quadratic equations by factorization:
`4/(x+2)-1/(x+3)=4/(2x+1)`
One of the roots of equation 5m2 + 2m + k = 0 is `(-7)/5` Complete the following activity to find the value of 'k'.
The number of quadratic equations having real roots and which do not change by squaring their roots is
Solve the following equation by factorization
x2 – 3x – 10 = 0
