Advertisements
Advertisements
प्रश्न
Solve equation using factorisation method:
`(x - 3)/(x + 3) + (x + 3)/(x - 3) = 2 1/2`
Advertisements
उत्तर
`(x - 3)/(x + 3) + (x + 3)/(x - 3) = 2 1/2`
⇒ `((x - 3)^2 + (x + 3)^2)/((x + 3) (x - 3)) = 5/2`
⇒ `(x^2 - 6x + 9 + x^2 + 6x + 9)/(x^2 - 9) = 5/2`
⇒ 2(2x2 + 18) = 5(x2 – 9)
⇒ 4x2 + 36 = 5x2 – 45
⇒ x2 – 81 = 0
⇒ x2 – 92 = 0
⇒ (x + 9)(x – 9) = 0
If x + 9 = 0 or x – 9 = 0
Then x = – 9 or x = 9
APPEARS IN
संबंधित प्रश्न
The numerator of a fraction is 3 less than its denominator. If 2 is added to both the numerator and the denominator, then the sum of the new fraction and original fraction is `29/20`. Find the original fraction.
Solve the following quadratic equations by factorization:
25x(x + 1) = – 4
The hypotenuse of a right triangle is 25 cm. The difference between the lengths of the other two sides of the triangle is 5 cm. Find the lengths of these sides.
If the list price of a toy is reduced by Rs. 2, a person can buy 2 toys more for Rs. 360. Find the original price of the toy.
Find the two consecutive positive odd integers whose product is 483.
A two digit number is such that the product of the digits is 14. When 45 is added to the number, then the digit are reversed. Find the number.
The sum of the square of 2 positive integers is 208. If the square of larger number is 18 times the smaller number, find the numbers.
Solve equation using factorisation method:
x(x – 5) = 24
A car covers a distance of 400 km at a certain speed. Had the speed been 12 km/hr more, the time taken for the journey would have been 1 hour 40 minutes less. Find the original speed of the car.
A man spent Rs. 2800 on buying a number of plants priced at Rs x each. Because of the number involved, the supplier reduced the price of each plant by Rupee 1.The man finally paid Rs. 2730 and received 10 more plants. Find x.
