Advertisements
Advertisements
प्रश्न
The sum of a number and its reciprocal is `2 9/40`. Find the number.
Advertisements
उत्तर
Let the number be A. Then as per the question,
`"A" + 1/ "A" = 2 9/40`
⇒ `"A"^2 + 1 - 89/40 "A" = 0`
⇒ 40 A2 + 40 - 89 A=0
⇒ 40A2 - 89A + 40 = 0
⇒ 40 A2 - 64A - 25A + 40 = 0
⇒ 8A (5A - 8) - 5 (5A-8) = 0
⇒ (8A - 5)(5A - 8) = 0
⇒ A = `5/8 , 8/5`
APPEARS IN
संबंधित प्रश्न
The length of a hall is 5 m more than its breadth. If the area of the floor of the hall is 84 m2, what are the length and breadth of the hall?
If sin α and cos α are the roots of the equations ax2 + bx + c = 0, then b2 =
Solve the following equation : x2 + 2ab = (2a + b)x
Solve the following quadratic equation using formula method only
6x2 + 7x - 10 = 0
A two digit positive number is such that the product of its digits is 6. If 9 is added to the number, the digits interchange their places. Find the number.
Solve the following quadratic equation by factorisation:
(x - 4) (x + 2) = 0
In each of the following determine whether the given values are solutions of the equation or not.
6x2 - x - 2 = 0; x = `-(1)/(2), x = (2)/(3)`
Solve the following equation by factorization
`x/(x - 1) + (x - 1)/x = 2(1)/(2)`
If twice the area of a smaller square is subtracted from the area of a larger square, the result is 14 cm2. However, if twice the area of the larger square is added to three times the area of the smaller square, the result is 203 cm2. Determine the sides of the two squares.
Find the roots of the following quadratic equation by the factorisation method:
`21x^2 - 2x + 1/21 = 0`
