Advertisements
Advertisements
प्रश्न
Solve the following quadratic equation by factorisation:
(x - 4) (x + 2) = 0
Advertisements
उत्तर
The given quadratic equation is
(x - 4) (x + 2) = 0
⇒ x - 4 = 0 or x + 2 = 0
⇒ x = {4, -2}.
संबंधित प्रश्न
The hypotenuse of a right triangle is `3sqrt10`. If the smaller leg is tripled and the longer leg doubled, new hypotenuse wll be `9sqrt5`. How long are the legs of the triangle?
Sum of the areas of two squares is 640 m2. If the difference of their perimeters is 64 m. Find the sides of the two squares.
Solve each of the following equations by factorization:
`x=(3x+1)/(4x)`
If y = 1 is a common root of the equations \[a y^2 + ay + 3 = 0 \text { and } y^2 + y + b = 0\], then ab equals
Solve the following equation : `"ax"^2 + (4"a"^2 - 3"b")"x" - 12"ab" = 0`
The perimeter of the right angled triangle is 60cm. Its hypotenuse is 25cm. Find the area of the triangle.
Solve the following quadratic equation:
4x2 - 4ax + (a2 - b2) = 0 where a , b ∈ R.
Solve the following by reducing them to quadratic form:
`sqrt(y + 1) + sqrt(2y - 5) = 3, y ∈ "R".`
If α and β are roots of the quadratic equation x2 – 7x + 10 = 0, find the quadratic equation whose roots are α2 and β2.
For equation `1/x + 1/(x - 5) = 3/10`; one value of x is ______.
