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Question
Find the value of the following:
`tan^(-1) (tan (7pi)/6)`
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Solution
`tan^(-1) (tan (7pi)/6) ≠ (7pi)/6` as the range of the principal value branch of tan−1 is `(-pi/2, pi/2)`.
So, `tan^(-1) (tan (7pi)/6)`
= `tan^-1(tan(pi + pi/6))`
= `tan^-1(tan pi/6)`
= `pi/6`
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