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Find the value of the following: tan-1(tan 7π/6) - Mathematics

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प्रश्न

Find the value of the following:

`tan^(-1) (tan  (7pi)/6)`

योग
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उत्तर

`tan^(-1) (tan  (7pi)/6) ≠ (7pi)/6` as the range of the principal value branch of tan−1 is `(-pi/2, pi/2)`.

So, `tan^(-1) (tan  (7pi)/6)`

= `tan^-1(tan(pi + pi/6))`

= `tan^-1(tan  pi/6)`

= `pi/6`

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अध्याय 2: Inverse Trigonometric Functions - Exercise 2.3 [पृष्ठ ५१]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 2 Inverse Trigonometric Functions
Exercise 2.3 | Q 2 | पृष्ठ ५१

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