Advertisements
Advertisements
Question
Find the value of: `(5(26!) + (27!))/(4(27!) - 8(26!)`
Advertisements
Solution
`(5(26!) + (27!))/(4(27!) - 8(26!)`
= `(5(26!) + 27(26!))/(4(27xx26!) - 8(26!)`
= `(26!(5 + 27))/(4(26!)(27-2))`
= `32/((4)(25))`
= `(8)/(25)`
APPEARS IN
RELATED QUESTIONS
A teacher wants to select the class monitor in a class of 30 boys and 20 girls. In how many ways can he select a student if the monitor can be a boy or a girl?
Evaluate: 6!
Evaluate: 8! – 6!
Evaluate: (8 – 6)!
Compute: `(12/6)!`
Compute: (3 × 2)!
Compute: 3! × 2!
Compute: `(9!)/(3! 6!)`
Compute: `(8!)/((6 - 4)!)`
Write in terms of factorial:
5 × 6 × 7 × 8 × 9 × 10
Write in terms of factorial:
3 × 6 × 9 × 12 × 15
Write in terms of factorial:
5 × 10 × 15 × 20 × 25
Evaluate: `("n"!)/("r"!("n" - "r"!)` For n = 8, r = 6
Find n, if (n + 3)! = 110 × (n + 1)!
Find n, if: `((17 - "n")!)/((14 - "n")!)` = 5!
Find n, if: `((2"n")!)/(7!(2"n" - 7)!) : ("n"!)/(4!("n" - 4)!)` = 24:1
Show that
`("n"!)/("r"!("n" - "r")!) + ("n"!)/(("r" - 1)!("n" - "r" + 1)!) = (("n" + 1)!)/("r"!("n" - "r" + 1)!`
A student passes an examination if he/she secures a minimum in each of the 7 subjects. Find the number of ways a student can fail.
