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प्रश्न
Find the value of: `(5(26!) + (27!))/(4(27!) - 8(26!)`
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उत्तर
`(5(26!) + (27!))/(4(27!) - 8(26!)`
= `(5(26!) + 27(26!))/(4(27xx26!) - 8(26!)`
= `(26!(5 + 27))/(4(26!)(27-2))`
= `32/((4)(25))`
= `(8)/(25)`
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संबंधित प्रश्न
How many five-digit numbers formed using the digit 0, 1, 2, 3, 4, 5 are divisible by 3 if digits are not repeated?
Evaluate: 8!
Compute: `(12!)/(6!)`
Compute: `(9!)/(3! 6!)`
Compute: `(8!)/(6! - 4!)`
Write in terms of factorial:
3 × 6 × 9 × 12 × 15
Write in terms of factorial:
6 × 7 × 8 × 9
Evaluate: `("n"!)/("r"!("n" - "r"!)` For n = 8, r = 6
Evaluate: `("n"!)/("r"!("n" - "r"!)` For n = 12, r = 12
Find n, if `"n"/(8!) = 3/(6!) + 1/(4!)`
Find n, if `"n"/(6!) = 4/(8!) + 3/(6!)`
Find n, if `1/("n"!) = 1/(4!) - 4/(5!)`
Find n if: `("n"!)/(3!("n" - 3)!) : ("n"!)/(5!("n" - 5)!)` = 5:3
Find n, if: `((15 - "n")!)/((13 - "n")!)` = 12
Show that: `(9!)/(3!6!) + (9!)/(4!5!) = (10!)/(4!6!)`
Find the value of: `(8! + 5(4!))/(4! - 12)`
A hall has 12 lamps and every lamp can be switched on independently. Find the number of ways of illuminating the hall.
