Advertisements
Advertisements
Question
Write in terms of factorial:
5 × 10 × 15 × 20 × 25
Advertisements
Solution
5 × 10 × 15 × 20 × 25
= (5 × 1) × (5 × 2) × (5 × 3) × (5 × 4) × (5 × 5)
= (55) (5 × 4 × 3 × 2 × 1)
= (55) (5!)
APPEARS IN
RELATED QUESTIONS
Evaluate: 8!
Evaluate: 8! – 6!
Evaluate: (8 – 6)!
Compute: `(12/6)!`
Compute: (3 × 2)!
Compute: `(6! - 4!)/(4!)`
Compute: `(8!)/((6 - 4)!)`
Write in terms of factorial:
6 × 7 × 8 × 9
Evaluate: `("n"!)/("r"!("n" - "r"!)` For n = 8, r = 6
Evaluate: `("n"!)/("r"!("n" - "r"!)` For n = 12, r = 12
Find n, if `1/("n"!) = 1/(4!) - 4/(5!)`
Find n, if (n + 1)! = 42 × (n – 1)!
Show that: `(9!)/(3!6!) + (9!)/(4!5!) = (10!)/(4!6!)`
A student passes an examination if he/she secures a minimum in each of the 7 subjects. Find the number of ways a student can fail.
Five balls are to be placed in three boxes, where each box can contain up to five balls. Find the number of ways if no box is to remain empty.
A question paper has 6 questions. How many ways does a student have if he wants to solve at least one question?
