Advertisements
Advertisements
Question
A question paper has 6 questions. How many ways does a student have if he wants to solve at least one question?
Advertisements
Solution
Every question is ‘SOLVED’ or ‘NOT SOLVED’.
There are 6 questions.
Number of outcomes = 26
This number includes the case when the student solves NONE of the questions.
Required number = 26 – 1 = 64 – 1 = 63
APPEARS IN
RELATED QUESTIONS
How many three-digit numbers can be formed using the digits 2, 3, 4, 5, 6 if digits can be repeated?
If numbers are formed using digits 2, 3, 4, 5, 6 without repetition, how many of them will exceed 400?
Evaluate: 8!
Evaluate: 6!
Evaluate: 8! – 6!
Compute: `(12!)/(6!)`
Compute: `(12/6)!`
Compute: `(6! - 4!)/(4!)`
Compute: `(8!)/(6! - 4!)`
Compute: `(8!)/((6 - 4)!)`
Evaluate: `("n"!)/("r"!("n" - "r"!)` For n = 8, r = 6
Find n, if (n + 1)! = 42 × (n – 1)!
Find n, if (n + 3)! = 110 × (n + 1)!
Find n if: `("n"!)/(3!("n" - 3)!) : ("n"!)/(5!("n" - 5)!)` = 5:3
Show that: `(9!)/(3!6!) + (9!)/(4!5!) = (10!)/(4!6!)`
A student passes an examination if he/she secures a minimum in each of the 7 subjects. Find the number of ways a student can fail.
A hall has 12 lamps and every lamp can be switched on independently. Find the number of ways of illuminating the hall.
How many quadratic equations can be formed using numbers from 0, 2, 4, 5 as coefficient if a coefficient can be repeated in an equation.
