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Question
Find n, if `"n"/(6!) = 4/(8!) + 3/(6!)`
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Solution
`"n"/(6!) = 4/(8!) + 3/(6!)`
∴ `"n"/(6!)-3/(6!)=4/(8!)`
∴ `("n"-3)/(6!)=4/(8 xx 7 xx 6!)`
∴ n − 3 = `4/(8xx7)`
∴ n − 3 = `1/14`
∴ n = `1/14+3=(43)/(14)`
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