Advertisements
Advertisements
प्रश्न
Find n, if `"n"/(6!) = 4/(8!) + 3/(6!)`
Advertisements
उत्तर
`"n"/(6!) = 4/(8!) + 3/(6!)`
∴ `"n"/(6!)-3/(6!)=4/(8!)`
∴ `("n"-3)/(6!)=4/(8 xx 7 xx 6!)`
∴ n − 3 = `4/(8xx7)`
∴ n − 3 = `1/14`
∴ n = `1/14+3=(43)/(14)`
APPEARS IN
संबंधित प्रश्न
A teacher wants to select the class monitor in a class of 30 boys and 20 girls, in how many ways can the monitor be selected if the monitor must be a boy? What is the answer if the monitor must be a girl?
How many five-digit numbers formed using the digit 0, 1, 2, 3, 4, 5 are divisible by 3 if digits are not repeated?
Evaluate: 8!
Evaluate: 6!
Compute: `(12!)/(6!)`
Compute: `(12/6)!`
Compute: (3 × 2)!
Compute: 3! × 2!
Write in terms of factorial:
5 × 10 × 15 × 20 × 25
Find n, if (n + 1)! = 42 × (n – 1)!
Find n, if (n + 3)! = 110 × (n + 1)!
Show that
`("n"!)/("r"!("n" - "r")!) + ("n"!)/(("r" - 1)!("n" - "r" + 1)!) = (("n" + 1)!)/("r"!("n" - "r" + 1)!`
Find the value of: `(8! + 5(4!))/(4! - 12)`
Show that: `((2"n")!)/("n"!)` = 2n(2n – 1)(2n – 3)....5.3.1
A student passes an examination if he/she secures a minimum in each of the 7 subjects. Find the number of ways a student can fail.
A hall has 12 lamps and every lamp can be switched on independently. Find the number of ways of illuminating the hall.
