Advertisements
Advertisements
प्रश्न
Find n, if `"n"/(8!) = 3/(6!) + 1/(4!)`
Advertisements
उत्तर
`"n"/(8!) = 3/(6!) + 1/(4!)`
∴ `"n"/(8!)=3/(6!)+(6xx5)/(6xx5xx4!)`
∴ `"n"/(8!)=3/(6!)+30/(6!)`
∴ `"n"/(8xx7xx6!) = 33/(6!)`
∴ `"n"/56` = 33
∴ n = 56 × 33 = 1848
APPEARS IN
संबंधित प्रश्न
How many three-digit numbers can be formed using the digits 2, 3, 4, 5, 6 if digits can be repeated?
Evaluate: 8!
Evaluate: 8! – 6!
Compute: (3 × 2)!
Compute: `(8!)/((6 - 4)!)`
Write in terms of factorial:
5 × 6 × 7 × 8 × 9 × 10
Evaluate: `("n"!)/("r"!("n" - "r"!)` For n = 8, r = 6
Find n, if `1/("n"!) = 1/(4!) - 4/(5!)`
Find n, if (n + 3)! = 110 × (n + 1)!
Find n if: `("n"!)/(3!("n" - 3)!) : ("n"!)/(5!("n" - 5)!)` = 5:3
Find n, if: `((17 - "n")!)/((14 - "n")!)` = 5!
Find n, if: `((15 - "n")!)/((13 - "n")!)` = 12
Find the value of: `(8! + 5(4!))/(4! - 12)`
Find the value of: `(5(26!) + (27!))/(4(27!) - 8(26!)`
A student passes an examination if he/she secures a minimum in each of the 7 subjects. Find the number of ways a student can fail.
How many quadratic equations can be formed using numbers from 0, 2, 4, 5 as coefficient if a coefficient can be repeated in an equation.
