Advertisements
Advertisements
प्रश्न
Find n, if `1/("n"!) = 1/(4!) - 4/(5!)`
Advertisements
उत्तर
`1/("n"!) = 1/(4!) - 4/(5!)`
∴ `1/("n"!) = 1/(4!) - 4/(5!)`
∴ `1/("n"!) = 5/(5xx4!)- 4/(5!)`
∴ `1/("n"!) = 5/(5!)-4/(5!)`
∴ `1/("n"!) = 1/(5!)`
∴ n! = 5!
∴ n = 5
APPEARS IN
संबंधित प्रश्न
A teacher wants to select the class monitor in a class of 30 boys and 20 girls. In how many ways can he select a student if the monitor can be a boy or a girl?
A teacher wants to select the class monitor in a class of 30 boys and 20 girls, in how many ways can the monitor be selected if the monitor must be a boy? What is the answer if the monitor must be a girl?
If numbers are formed using digits 2, 3, 4, 5, 6 without repetition, how many of them will exceed 400?
Evaluate: 6!
Evaluate: 8! – 6!
Evaluate: (8 – 6)!
Compute: `(12!)/(6!)`
Compute: `(12/6)!`
Compute: (3 × 2)!
Compute: 3! × 2!
Compute: `(9!)/(3! 6!)`
Write in terms of factorial:
3 × 6 × 9 × 12 × 15
Evaluate: `("n"!)/("r"!("n" - "r"!)` For n = 8, r = 6
Find n, if (n + 3)! = 110 × (n + 1)!
Show that
`("n"!)/("r"!("n" - "r")!) + ("n"!)/(("r" - 1)!("n" - "r" + 1)!) = (("n" + 1)!)/("r"!("n" - "r" + 1)!`
Show that: `(9!)/(3!6!) + (9!)/(4!5!) = (10!)/(4!6!)`
Find the value of: `(8! + 5(4!))/(4! - 12)`
How many quadratic equations can be formed using numbers from 0, 2, 4, 5 as coefficient if a coefficient can be repeated in an equation.
