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Find the sum of all 2-digit natural numbers divisible by 5.

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Question

Find the sum of all 2-digit natural numbers divisible by 5.

Sum
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Solution

The numbers are 10, 15, 20, ..., 95.

Here $$a = 10,\ d = 5, \ l = 95$$. 

Number of terms: $$n = \frac{95 - 10}{5} + 1 = 18$$. 

Sum $$S_{18} = \frac{18}{2}(10 + 95)$$

$$= 9(105)$$

$$= 945$$

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Chapter 10: Arithmetic Progression - EXERCISE 10B [Page 167]

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R.S. Aggarwal Mathematics [English] Class 10 ICSE
Chapter 10 Arithmetic Progression
EXERCISE 10B | Q 9. | Page 167
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